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±âÃʺ¸´Ù : ±âÃÊÀüÀÚ±âÇÐ 3ÆÇ ´ëÇб³Àç¼Ö·ç¼Ç David J. Griffiths Introduction To Electrodynamics Solutions

±âÃÊÀüÀÚ±âÇÐ 3ÆÇ David J. Griffiths Introduction To Electrodynamics Solutions ¼Ö·ç¼Ç ÀÔ´Ï´Ù. ÃÑ 253ÆäÀÌÁö ÀÔ´Ï´Ù..

INSTRUCTOR`S SOLUTIONS MANUAL

INTRODUCTION to ELECTRODYNAMICS
Third Edition

David J. Griffiths

Errata Instructor¡¯s Solutions Manual Introduction to Electrodynamics, 3rd ed Author: David Gri?ths Date: September 1, 2004 ? Page 4, Prob. 1.15 (b): last expression should read y + 2z + 3x. ? Page 4, Prob.1.16: at the beginning, insert the following ?gure

? Page 8, Prob. 1.26: last line should read From Prob. 1.18: ¡Ô ¡¿ va = ?6xz x + 2z y + 3z 2 ? ¢¡ ? ? z ¡Ô ¡¤ (¡Ô ¡¿ va ) =
¡Ó ¡Óx (?6xz)

+

¡Ó ¡Óy (2z)

+

¡Ó 2 ¡Óz (3z )

= ?6z + 6z = 0.

? Page 8, Prob. 1.27, in the determinant for ¡Ô¡¿(¡Ôf ), 3rd row, 2nd column: change y 3 to y 2 . ? Page 8, Prob. 1.29, line 2: the number in the box should be -12 (insert minus sign). ? Page 9, Prob. 1.31, line 2: change 2x3 to 2z 3 ; ?rst line of part (c): insert comma between dx and dz. ? Page 12, Probl 1.39, line 5: remove comma after cos ¥è. ? Page 13, Prob. 1.42(c), last line: insert ? after ). z ? Page 14, Prob. 1.46(b):



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