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 workbook : ¸Æ±×·ÎÈú ȸ·ÎÀÌ·Ð 4ÆÇ ¼Ö·ç¼Ç McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th Ç®ÀÌ




workbook : ¸Æ±×·ÎÈú ȸ·ÎÀÌ·Ð 4ÆÇ ¼Ö·ç¼Ç McGRAW HILL 4th Fundamentals of Electric Circuits McGRAW HILL 4th

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practice problem
problem
Problem Solving WorkbookChapter 1, Problem 1
How many coulombs are represented by these amounts of electrons:
(a) (b) 1710482.6¡¿181024.1¡¿
(c) (d) 191046.2¡¿2010628.1¡¿
Chapter 1, Solution 1
(a) q = 6.482x1017 x [-1.602x10-19 C] = -0.10384 C
(b) q = 1. 24x1018 x [-1.602x10-19 C] = -0.19865 C
(c) q = 2.46x1019 x [-1.602x10-19 C] = -3.941 C
(d) q = 1.628x1020 x [-1.602x10-19 C] = -26.08 C
Chapter 1, Problem 2.
Determine the current flowing through an element if the charge flow is given by
(a) ()()mC 83+=ttq
(b) ()C 2)482t-t(tq+=
(c) ()()nC e5e3tqt2-t−−=
(d) ()pCt sin10 120tq¥ð=
(e) ()Ct 50cos204¥ìtetq−=
Chapter 1, Solution 2
(a) i = dq/dt = 3 mA
(b) i = dq/dt = (16t + 4) A
(c) i = dq/dt = (-3e-t + 10e-2t) nA
(d) i=dq/dt = 1200120¥ð¥ðcost pA
(e) i =dq/dt = −+−ettt48050100050(cossin) A¥ì
PROPRIETARY MATERIAL. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. No part
of this Manual may be displayed, reproduced or distributed in any form or by any



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